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#37329
frankr
Participant

    Ground to red is meaningless. Well, maybe if you want to do some math… Anyhoo, you would be testing all six at the same time. But suppose one was open? Look at the diagram above.There are 3 pairs of two diodes in series. Suppose the upper left one is open. That would be the same as taking it right out of the picture and leaving a gap where it was. The two right columns would still pass current in one direction and block it in the other direction (as they should). But the remaining good one in the left column would not be doing anything either way because current can’t even get to it through the open gap.

    So the rectifier would seemingly pass (passing current in only one direction), but in fact it has that bad diode.

    Make sense?